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leetcode - 1661. Average Time of Process per MachineSQL 문제풀이 2022. 7. 22. 15:19
난이도 : Easy
Table: Activity
+----------------+---------+ | Column Name | Type | +----------------+---------+ | machine_id | int | | process_id | int | | activity_type | enum | | timestamp | float | +----------------+---------+ The table shows the user activities for a factory website. (machine_id, process_id, activity_type) is the primary key of this table. machine_id is the ID of a machine. process_id is the ID of a process running on the machine with ID machine_id. activity_type is an ENUM of type ('start', 'end'). timestamp is a float representing the current time in seconds. 'start' means the machine starts the process at the given timestamp and 'end' means the machine ends the process at the given timestamp. The 'start' timestamp will always be before the 'end' timestamp for every (machine_id, process_id) pair.There is a factory website that has several machines each running the same number of processes. Write an SQL query to find the average time each machine takes to complete a process.
The time to complete a process is the 'end' timestamp minus the 'start' timestamp. The average time is calculated by the total time to complete every process on the machine divided by the number of processes that were run.
The resulting table should have the machine_id along with the average time as processing_time, which should be rounded to 3 decimal places.
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input: Activity table: +------------+------------+---------------+-----------+ | machine_id | process_id | activity_type | timestamp | +------------+------------+---------------+-----------+ | 0 | 0 | start | 0.712 | | 0 | 0 | end | 1.520 | | 0 | 1 | start | 3.140 | | 0 | 1 | end | 4.120 | | 1 | 0 | start | 0.550 | | 1 | 0 | end | 1.550 | | 1 | 1 | start | 0.430 | | 1 | 1 | end | 1.420 | | 2 | 0 | start | 4.100 | | 2 | 0 | end | 4.512 | | 2 | 1 | start | 2.500 | | 2 | 1 | end | 5.000 | +------------+------------+---------------+-----------+ Output: +------------+-----------------+ | machine_id | processing_time | +------------+-----------------+ | 0 | 0.894 | | 1 | 0.995 | | 2 | 1.456 | +------------+-----------------+ Explanation: There are 3 machines running 2 processes each. Machine 0's average time is ((1.520 - 0.712) + (4.120 - 3.140)) / 2 = 0.894 Machine 1's average time is ((1.550 - 0.550) + (1.420 - 0.430)) / 2 = 0.995 Machine 2's average time is ((4.512 - 4.100) + (5.000 - 2.500)) / 2 = 1.456WITH start AS ( SELECT machine_id , process_id , activity_type , timestamp FROM Activity WHERE activity_type = 'start' ) ,end AS ( SELECT machine_id , process_id , activity_type , timestamp FROM Activity WHERE activity_type = 'end' ) ,step1 AS ( SELECT start.machine_id , start.process_id , end.timestamp - start.timestamp processing_time FROM start JOIN end ON start.machine_id = end.machine_id AND start.process_id = end.process_id GROUP BY machine_id, process_id ) SELECT machine_id , ROUND(AVG(processing_time), 3) processing_time FROM step1 GROUP BY machine_idAccepted (78.65%)
WITH sub AS ( SELECT machine_id , process_id , MAX(timestamp) end , MIN(timestamp) start FROM Activity GROUP BY 1, 2 ) SELECT machine_id , ROUND(SUM(end - start) / COUNT(distinct process_id), 3) processing_time FROM sub GROUP BY 1Accepted (87.19%)
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