leetcode - 577. Employee Bonus

난이도 : Easy

 

Table: Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| empId       | int     |
| name        | varchar |
| supervisor  | int     |
| salary      | int     |
+-------------+---------+
empId is the primary key column for this table.
Each row of this table indicates the name and the ID of an employee in addition to their salary and the id of their manager.

 

Table: Bonus

+-------------+------+
| Column Name | Type |
+-------------+------+
| empId       | int  |
| bonus       | int  |
+-------------+------+
empId is the primary key column for this table.
empId is a foreign key to empId from the Employee table.
Each row of this table contains the id of an employee and their respective bonus.

 

Write an SQL query to report the name and bonus amount of each employee with a bonus less than 1000.

Return the result table in any order.

 

 

join을 활용한 방법

SELECT Employee.name
     , bonus
FROM Employee
     LEFT JOIN Bonus ON Employee.empId = Bonus.empId
WHERE bonus < 1000
OR bonus IS NULL

Accepted (94.55%)

 

 

ifnull을 활용한 방법

SELECT Employee.name
     , bonus
FROM Employee
     LEFT JOIN Bonus ON Employee.empId = Bonus.empId
WHERE IFNULL(bonus, 0) < 1000

Accepted (13.56%)