leetcode - DescriptionSolutionDiscuss (50)Submissions2292. Products With Three or More Orders in Two Consecutive Years

난이도 : Medium

 

Table: Orders

+---------------+------+
| Column Name   | Type |
+---------------+------+
| order_id      | int  |
| product_id    | int  |
| quantity      | int  |
| purchase_date | date |
+---------------+------+
order_id is the primary key for this table.
Each row in this table contains the ID of an order, the id of the product purchased, the quantity, and the purchase date.

 

Write an SQL query to report the IDs of all the products that were ordered three or more times in two consecutive years.

Return the result table in any order.

The query result format is shown in the following example.

 

Example 1:

Input: 
Orders table:
+----------+------------+----------+---------------+
| order_id | product_id | quantity | purchase_date |
+----------+------------+----------+---------------+
| 1        | 1          | 7        | 2020-03-16    |
| 2        | 1          | 4        | 2020-12-02    |
| 3        | 1          | 7        | 2020-05-10    |
| 4        | 1          | 6        | 2021-12-23    |
| 5        | 1          | 5        | 2021-05-21    |
| 6        | 1          | 6        | 2021-10-11    |
| 7        | 2          | 6        | 2022-10-11    |
+----------+------------+----------+---------------+
Output: 
+------------+
| product_id |
+------------+
| 1          |
+------------+
Explanation: 
Product 1 was ordered in 2020 three times and in 2021 three times. Since it was ordered three times in two consecutive years, we include it in the answer.
Product 2 was ordered one time in 2022. We do not include it in the answer.

 

WITH sub AS (
            SELECT product_id
                 , YEAR(purchase_date) year
            FROM Orders
            GROUP BY 1, 2
            HAVING COUNT(order_id) >= 3
            )

SELECT distinct s1.product_id
FROM sub s1
     JOIN sub s2 ON s1.product_id = s2.product_id
                 AND s1.year = s2.year + 1

Accepted (39.53%)