SQL 문제풀이

leetcode - 1454. Active Users

Jerrytwo 2022. 8. 16. 15:39

난이도 : Medium

 

Table: Accounts

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| name          | varchar |
+---------------+---------+
id is the primary key for this table.
This table contains the account id and the user name of each account.

 

Table: Logins

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| login_date    | date    |
+---------------+---------+
There is no primary key for this table, it may contain duplicates.
This table contains the account id of the user who logged in and the login date. A user may log in multiple times in the day.

 

Active users are those who logged in to their accounts for five or more consecutive days.

Write an SQL query to find the id and the name of active users.

Return the result table ordered by id.

The query result format is in the following example.

 

Example 1:

Input: 
Accounts table:
+----+----------+
| id | name     |
+----+----------+
| 1  | Winston  |
| 7  | Jonathan |
+----+----------+
Logins table:
+----+------------+
| id | login_date |
+----+------------+
| 7  | 2020-05-30 |
| 1  | 2020-05-30 |
| 7  | 2020-05-31 |
| 7  | 2020-06-01 |
| 7  | 2020-06-02 |
| 7  | 2020-06-02 |
| 7  | 2020-06-03 |
| 1  | 2020-06-07 |
| 7  | 2020-06-10 |
+----+------------+
Output: 
+----+----------+
| id | name     |
+----+----------+
| 7  | Jonathan |
+----+----------+
Explanation: 
User Winston with id = 1 logged in 2 times only in 2 different days, so, Winston is not an active user.
User Jonathan with id = 7 logged in 7 times in 6 different days, five of them were consecutive days, so, Jonathan is an active user.

 

 

SELECT distinct l1.id
     , name
FROM Logins l1
     JOIN Logins l2 ON l1.id = l2.id
                    AND DATEDIFF(l2.login_date, l1.login_date) BETWEEN 1 AND 4
     LEFT JOIN Accounts ON l1.id = Accounts.id
GROUP BY l1.id, l1.login_date
HAVING COUNT(distinct l2.login_date) >= 4

Accepted (35.14%)