SQL 문제풀이

leetcode - 1459. Rectangles Area

Jerrytwo 2022. 8. 15. 18:25

난이도 : Medium

 

Table: Points

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| x_value       | int     |
| y_value       | int     |
+---------------+---------+
id is the primary key for this table.
Each point is represented as a 2D coordinate (x_value, y_value).

 

Write an SQL query to report all possible axis-aligned rectangles with a non-zero area that can be formed by any two points from the Points table.

Each row in the result should contain three columns (p1, p2, area) where:

  • p1 and p2 are the id's of the two points that determine the opposite corners of a rectangle.
  • area is the area of the rectangle and must be non-zero.

Return the result table ordered by area in descending order. If there is a tie, order them by p1 in ascending order. If there is still a tie, order them by p2 in ascending order.

The query result format is in the following table.

 

Example 1:

Input: 
Points table:
+----------+-------------+-------------+
| id       | x_value     | y_value     |
+----------+-------------+-------------+
| 1        | 2           | 7           |
| 2        | 4           | 8           |
| 3        | 2           | 10          |
+----------+-------------+-------------+
Output: 
+----------+-------------+-------------+
| p1       | p2          | area        |
+----------+-------------+-------------+
| 2        | 3           | 4           |
| 1        | 2           | 2           |
+----------+-------------+-------------+
Explanation: 
The rectangle formed by p1 = 2 and p2 = 3 has an area equal to |4-2| * |8-10| = 4.
The rectangle formed by p1 = 1 and p2 = 2 has an area equal to |2-4| * |7-8| = 2.
Note that the rectangle formed by p1 = 1 and p2 = 3 is invalid because the area is 0.

 

 

SELECT *
FROM (
      SELECT t1.id p1
           , t2.id p2
           , ABS((t1.x_value - t2.x_value) * (t1.y_value - t2.y_value)) area
      FROM Points t1
           JOIN Points t2 ON t1.id < t2.id
      ) sub
WHERE area <> 0
ORDER BY area desc, p1, p2

Accepted (57.48%)